A resistance of 2.5 Ohm is connected to 5V battery. The current and total charge flowing through the circuit in 3 minutes is?
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Step-by-step explanation:
Given that ;
Resistance(R)= 2.5 Ohm , Potential of the battery(V)=5 Volt , time = 3 min
To find- current ( I ) and the total charge (Q) flowing through the circuit in 3 minutes
So from the Ohms law we know the relation between R , V & I i.e.
- V= I*R , and here we know the values of R and V so by putting these value in this relation we get
- I = 5V/2.5Ohm On solving this we get
- I= 2 Ampere
- Now for the Calculation of the charge we know the formula Q= I*t
Given time is 3 min and we have to do the calculation as per S.I units that's that we have convert this value in second so
3 min = 3*60 =>180 sec as we know 1 min = 60 sec
Q = I*t
=> Q= 2Amp * 180 => 360 Coulombs or Amp *sec
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