Physics, asked by guptaaditya2518, 1 year ago

A resistance of 2 is connected across one gap of a metre bridge (the length of the wire is 100 cm) and an unknown resistance greater than 2 is connected across the other gap. When these resistances are interchanged, the balance point shifts by 20 cm . Neglecting any corrections, the unknown resistance is

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Answered by campon99
15
A resistance of 2 is connected across one gap of a metre bridge (the length of the wire is 100 cm) and an unknown resistance greater than 2 is connected across the other gap. When these resistances are interchanged, the....
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Answered by KaurSukhvir
1

Answer:

The value of unknown resistance will be equal to connected to second gap of the metre bridge.

Explanation:

Given that the length of the wire=100cm

One resistance =2Ω. and another resistance =x

From the first  given condition:

          \frac{R}{x} =\frac{I}{100-I}

         x=\frac{2(100-I)}{I}                                      ..................(1)

Second condition:

         \frac{x}{R} =\frac{I+20}{80-I}                                            .................(2)

Put the value of x from eq.(1) into Eq.(2)

       \frac{2(100-I)}{2I} =\frac{I+20}{80-I}

      (100-I)(80-I)=I(I+20)

      8000-100I-80I+I^{2}=I^{2}+20I\\

        8000=200I\\

 ∴        I=40cm

Put the value of I in eq. (1)

        x=\frac{2(40+20)}{80-40}

        x=\frac{120}{40}

∴      x=3Ω

Therefore is the value of unknown resistance which is connected across the other gap of the metre bridge.

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