Question

A resistance of 20 Ω, and a capacitance of 100 μF are connected in series across 220V, 50 Hz supply. Determine

(i) Impedance of the circuit

(ii) Current through the circuit

(iii) Voltage across Capacitance

(iv) Voltage across resistance

(v) power factor

(vi) power consumed in watts.

Answer 1

XC = 0.2 × 314 = 63Ω , C = 10μF = 100 × 10−6 = 10−4 farad XC = 1/ωC = 1/(314 x 10-4) = 32Ω, X = 63 − 32 = 31 Ω (inductive) (a) Z = √(202 + 31)2 = 37 Ω (b) I = 220/37 = 6 A (approx) (c) VR = I × R = 6 × 20 = 120 V; VL = 6 × 63 = 278 V, VC = 6 × 32 = 192 V (d) Power in VA = 6 × 220 = 1320 Power in watts = 6 × 220 × 0.54 = 713 W (e) p.f. = cos φ = R/Z = 20/37 = 0.54; φ = cos−1(0.54) = 57°18′Read more on Sarthaks.com - https://www.sarthaks.com/493275/resistance-of-20-an-inductance-of-and-capacitance-of-100-are-connected-in-series-across-220