Question

A resistance of 20 ohms has a current of 2 amperes flowing in it. What potential difference is there between it's end?

Answer 1

$\large\underline{ \underline{ \sf \: Solution : \: \: \: }}$

Given ,

$\star$Resistance (R) = 20 ohm

$\star$Current (I) = 2 amp

We know that ,

$\large \sf\fbox{ \fbox{ \: V = I × R \: \: }}$

$\sf \implies V = 2 \times 20 \\ \\\sf \implies V = 40 \: \: volt$

Hence , 40 volt is the required value of potential difference