Question

a resistance of 300ohm and inductance of 1/π henry are connected in series to AC voltage of 20v and 200hz frequency the phase angle between voltage and current?​

Answer 1

Answer:

The phase angle is tan^(-1)(4/3)

Explanation:

According to the problem the inductance ,i = 1/π resistance, r= 300 ohm

Now they both are connected in series.

Now let the phase angle between the voltage and current is,Ø

Therefore, tanØ = ωi/r [ where ω is the angular frequency]

Now we know ω = 2πf = 2π(200) = 400π

Now put all the values,

tanØ =  ωi/r = 400π x 1/π/ 300 = 4/3

Ø = tan^(-1)(4/3)