Question

A resistance of 40 ohm, a coil of inductive reactance 20 ohm and capacitor of capacitance reactance 50 ohm ,are connected across 250 V mains in series. the potential difference across the capacitor will be.​

Answer 1

The potential difference across the capacitor=250 V

Explanation:

Resistance =R=40 ohm

Inductive reactance$,X_L=20ohm$

Capacitve reactance=$x_C=$ 50 ohm

Potential difference=V=250 V

Impedance of RLC -series=$Z=\sqrt{R^2+(X_L-X_C)^2}$

Substitute the value in the formula

$Z=\sqrt{(40)^2+(20-50)^2}$

$Z=\sqrt{1600+900}=50$ohm

Current,I=$\frac{V}{Z}$

Current in the circuit=$I=\frac{250}{50}=5 A$

Potential difference across the capacitor=$V_C=X_CI$

Substitute the values

Potential difference across the capacitor=$5\times 50=250 V$

Hence, the potential difference across the capacitor=250 V

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