a resistance of 40 ohm and one of 60 ohm is suggested in series across 220v supply find heat in joule produce by this combination in half a minute
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Let R1 = 40 ohm
R2 = 60 ohm
A/c to question ,
R1 and R2 are in series combination,
so, equivalent Resistance (Req) = R1 + R2
Req = 40 + 60 = 100 ohm
now ,
we know ,
Heat = I²Rt
also , V = IR ( according to ohm' s law )
Heat = (V/R)² ×R × t
= V²× t/R
here,
Req = R = 100 ohm
V = 220 volt
t = 30 sec
then,
Heat = (220)² × 30/100 Joule
= 48400 × 30/100 Joule
= 484 × 30 Joule
= 14520 Joule
hence, heat = 14520 Joule
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