a resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply . find the heat in joules produced by this combination in half a minute .
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For a series combination of two or more resistors, the equivalent resistance of the circuit is the sum of the individual resistances. This means that for your circuit, the equivalent resistance will be 40 + 60 = 100 ohms.
Now, the total voltage applied across the combination is 220V.
Power dissipated in a load (here, the equivalent 100 ohm resistance) is given by the product of the current through, and voltage across it. That is, P = V*I. But we already know from ohm's law that the current through a load is equal to the voltage across it divided by its resistance (I = V/R). That makes our equation P = V*(V/R) = (V^2)/R = (220^2)/100 = 484 watts.
Finally, the energy released is given by power * time. That means, the energy released by the resistor combination is equal to the power dissipated by it, into the time for which it's been dissipating it. Hence, E = P*t = (484 watts)*(30 seconds) = 14520 joules = 14.52kJ
Now, the total voltage applied across the combination is 220V.
Power dissipated in a load (here, the equivalent 100 ohm resistance) is given by the product of the current through, and voltage across it. That is, P = V*I. But we already know from ohm's law that the current through a load is equal to the voltage across it divided by its resistance (I = V/R). That makes our equation P = V*(V/R) = (V^2)/R = (220^2)/100 = 484 watts.
Finally, the energy released is given by power * time. That means, the energy released by the resistor combination is equal to the power dissipated by it, into the time for which it's been dissipating it. Hence, E = P*t = (484 watts)*(30 seconds) = 14520 joules = 14.52kJ
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