Question

A resistance of 40ohm and 60ohm are arranged in series across 220v supply. Find the heat generated in 30 seconds

Answer 1

Hey!!!!

Good Afternoon

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We have,

R1 = 40 ohm

R2 = 60 ohm

All arranged in series

V = 220 V

t = 30 sec

Total Resistance = R1 + R2 (series)

=> Total Resistance (R) = 100 ohm

By Joule's Law of Heating

H = I²Rt ------(1)

By Ohm's Law

=> V = I x R

=> I = V/R

=> I = 220/100

=> I = 2.2 A

Using I in (1)

=> H = (2.2)²(100)(30)

=> H = (4.84)(100)(30)

=> H = 484(3)

=> H = 1452 J

Thus Heat generated in 30 seconds will be 1452 J

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Hope this helps ✌️