Question

A resistance of 40ohm and one of 60ohm are arranged in series across 220volt supply find the in joules proved by these combination in half a minutes

Answer 1

Resistance $(R_1)$ = 40 ohms

Resistance $(R_2)$ = 60 ohms

Total resistance of the circuit (R) = 40 + 60 = 100 ohms

Potential difference applied across the circuit = 220 Volts

Time for which the energy is consumed = half minute = 30 seconds

Energy supplied = $\frac{V^2 \times t}{R}$

$Energy = \frac{220 \times 220 \times 30}{100}$

Energy supplied = 1452 Joules

Hence, the energy supplied in 30 seconds is 1452 Joules.