A resistance of 50 Q and 100
inductive reactance are connected in
series across a 230 V, 50 Hz supply.
Calculate voltage drop across
inductor
O a. 205.71 V
O b. 102.5 V
O c. 100 V
O d. 153.71 V
Answers
Answered by
1
Explanation:
Z=
X
L
2
+R
2
=
(2πfL)
2
+R
2
=
(2π50×0.2)
2
+(100)
2
=
13947.84
=118.1Ω
i=
Z
V
=
118.1
180
=1.525A
Answered by
1
Answer:
hmm first one is correct
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