a resistance of 5ohm is connected in the left gap of a meter bridge and 15ohm in the other gap.sketch the diagram and then find the position of the balancing point.
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For meter bridge :-
X = R(100-l) / l
, where X & R are resistances & l is balancing length
Putting values :-
= 5 = 15(100-l) / l
= l = 300 - 3l
= 4l = 300
= l = 300/4 = 75cm
X = R(100-l) / l
, where X & R are resistances & l is balancing length
Putting values :-
= 5 = 15(100-l) / l
= l = 300 - 3l
= 4l = 300
= l = 300/4 = 75cm
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