A resistance of 6 Ω is connected in series with another resistance of 4 Ω. If a potential difference of 20 V
is applied across the combination, the current through the circuits is
A) 2A B) 0.2A C) 5A D) 3.3A
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Answer:
V=IR
v=20v
R= 6+4=10 ohm
I= 20÷10
=2A
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