Question

A resistance of 6 ohm is connected in series with another resistance of 4 ohm. A potential difference of 20 V is applied across the combination. Calculate the current through the circuit and potential difference across 6 ohm distance.

Answer 1

hey friend,

let resistance be R and R'

so R = 6 ohm

R' = 4 ohm

so resistance are connected in series

total resistance = R + R'

=6 + 4 = 10 ohm. current = potential difference/ resistance

= 20/10 = 2 ampere(A)

potential across 6 ohm resistor = I×R

= 2× 6 =12 volt


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hope it will help u

Answer 2

The current through the circuit and potential difference across a 6-ohm distance are 2 and 12 volt respectively.

Given:

A resistance of 6 ohms is connected in series with another resistance of 4 ohms. A potential difference of 20 V is applied across the combination.

To Find:

The potential difference across 6-ohm resistance.

Solution:

To find the potential difference across 6-ohm resistance. we will follow the following steps:

As we know, in the series sum of resistance gives total resistance to the circuit. so, the total resistance is 6 + 4 = 10 Ohm.

Current through the circuit × resistance = voltage.

V = IR

$i \: = \frac{v}{r} = \frac{20}{10} = 2ampere$

In series same current flows through both the resistance.

So,

The voltage across 6-ohm resistance will be calculated as V = IR.

= 2×6 = 12V

Henceforth, the current through the circuit and potential difference across a 6-ohm distance are 2 and 12 volt respectively.

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