Question

a resistance of 6 ohm is connected in series with another resistance of 4 ohm connected across a battery of 20v . find net resistance,total current,and potential difference across each resistance
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Answer 1

$\huge\sf\pink{Answer}$

☞ Net Resistance is 10Ω, Current = 2 A

☞ PD across the 6Ω resistor is 12 V & accross the 4Ω resistor is 8 V

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$\huge\sf\blue{Given}$

✭ Resistor of 6Ω & 4Ω are connected in series

✭ Voltage = 20 V

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$\huge\sf\gray{To \:Find}$

◈ Net resistance?

◈ Total Current?

◈ Potential difference across each resistance?

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$\huge\sf\purple{Steps}$

Question 1

Net resistance of a series connection is given by,

$\underline{\boxed{\sf R_{net} = R_1+R_2+R_3...R_n}}$

Substituting the given values,

➝ $\sf R_{net} = 6 \Omega + 4\Omega$

➝ $\sf \red{R_{net} = 10\Omega}$

Question 2

To find the current we shall use the Ohm's law, that is,

$\underline{\boxed{\sf V=IR}}$

Substituting the given values,

➳ $\sf V=IR$

➳ $\sf 20 = 1\times 10$

➳ $\sf 20 = 10I$

➳ $\sf \dfrac{20}{10} = I$

➳ $\sf \green{I = 2 \ A}$

Question 3

Unlike parallel connection in a series connection the voltage varies but the current remains constant,so to find the pd across the resistors we shall use the Ohm's law (V=IR)

PD across the 6Ω Resistor

»» $\sf V=IR$

»» $\sf V=2 \times 6$

»» $\sf \orange{PD=12 \ V}$

PD across the 4Ω Resistor

»» $\sf V=IR$

»» $\sf V=2\times 4$

»» $\sf \orange{PD=8 \ V}$

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