A resistance of 6 ohm is connected in series with other resistance of 4 ohms. A potential difference of 20 volts is applied across the combination. Calculate the current through the circuit and potential difference across the 6 ohm resistance.
Answers
Answer:
The answer is 2A
Explanation:
Here resistance=6+4=10
Potential difference= 20v
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Therefore I=V/R
I=20/10
= 2 A
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"Hope it will help"
ANSWER :
Given :
▪ A resistor of resistance 6Ω is connected in series with another resistor of resistance 4Ω.
▪ Potential difference = 20V
To Find :
▪ Current flow in the circuit and potential difference across 6Ω resistor.
Concept :
→ First we have to find out equivalent resistance of the series connection.
→ After that we can calculate current flow and potential difference with the help of ohm's law.
→ Formula of equivalent resistance for series connection is given by
✴ Req = R1 + R2
→ As per ohm's law, relation b/w potential difference and current flow is given by
✴ V = IR
Calculation :
✏ Equivalent resistance :
☞ Req = R1+R2
☞ Req = 6+4
☞ Req = 10Ω
✏ Current flow in circuit :
☞ V = I(Req)
☞ 20 = 10×I
☞ I = 20/10
☞ I = 2A
✏ Potential difference across R1 :
☞ V' = I(R1)
☞ V' = 2×6