Question

A resistance of 6 ohms is connected in series with another resistance of 4

ohms. A potential difference of 20 volts is applied across the combination.

Calculate the current through the circuit and potential difference across

the 6 ohm resistance

Answer 1

In series, the total resistance is 10 ohms. Using Ohm’s law, V = IR, I = V/R, and I = 20/10 = 2A

The 20V is divided among the resistors in an inverse proportion, with the lower resistance dissipating more power and therefore more voltage (since the current through both resistors is the same). But since we already know how much current is passing through the 6 ohm resistor (2A), we can just use Ohm’s law again.

V = IR … V=2*6 = 12V

Answer 2

hey mate here is the answer !!!!

as the resistance are connected in series
so r1 + r2 = 6 +4 = 10. ohm

now , v = ir
I= v/r
I = 20/10
I = 2 ampere

so. 2 a current flow through circuit ...

now , PD. across the 6 ohm ,,

v = ir
v = 2×6 = 12volt

now I = v/r
I = 12/6 = 2 ampere

and we know that the same current flow through each of the resistance in series ,,

hope it helps !!!

♠ himanshu Jha ♠