a resistance of 6 ohms is connected in series with another resistance of 4 ohm .a potential difference of 20 volts is applied across the combination.calculate the current through the circuit and the potential difference at the ends of the conductor
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in series r=r1+r2
r=6+4=10ohm
i=v/r
i=20/10
i=2A
r=6+4=10ohm
i=v/r
i=20/10
i=2A
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