A resistance of 75 ohms is connected in shunt of the galvanometer, having an internal resistance of 25 ohms, to convert it into an ammeter. What is the value of current (in
a.Flowing through the galvanometer, if the total current in the circuit is 5 a?
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As we know that,
v=I/R
so, I=v*R
l=5*25
I=125columb.
v=I/R
so, I=v*R
l=5*25
I=125columb.
Answered by
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Answer:
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