A resistance of 9 ohm is connected to a cell.a voltmeter connected across the cell reads 1.8v When a resistance of 10 ohm is connected in series with 9 ohm the voltmeter reading changes to 1.9v calculate the EMF Of the cell and its internal resistance
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Answer: This may help you
Explanation:
£=I(R+r)=1.8v+0.2r. I=v/r=1.8v/9ohm=0.2A
£=I(R+r)=1.9v+0.1r. I=v/r=1.9v/9ohm=0.1A
1.8v+0.2r=1.9v+0.1r
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2.0-answer is the correct .
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