Question

a resistance per meter length of a wire is 10 ohm .if the resistivity of the material ia 50*10∧-8 ohm meter.find the area of cross section of the wire

Answer 1

R=pl/a
where, R=resistance of the wire
p=resistivity of the wire
l=length of wire
a=area of cross section
=>R/l =p/a
=>10=50×10^-8/a
=>a=50×10^-9m²

Answer 2

$\underline\bold{\huge {solution!!}}$

R = 10 ohm

$Rho = 50 × 10^-8$
$R = \frac { rho × Length}{area of cross-section}$

$A = \frac { rho × Length}{R}$

$A = \frac { 50×10^-8 × 1}{10}$

$A = 5 × 10^-8$

or

$A = 50 × 10^-9$

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