A resistance 'R' draws power 'P' when connected to an AC
source. If an inductance is now placed in series with the
resistance, such that the impedance of the circuit becomes
'Z', the power drawn will be [2015]
(a) P √R/Z
(b) P (R/Z)
(c) P (d) P (R/Z)²
Answers
Answered by
2
Answer:
Power P=irms2R=(RVrms)2R
Power when inductor is put in series with R: P′=(ZVrms)2R
PP′=R2RZ2R=(ZR)2
P′=P(ZR)2 Please mark the answer as the branliest
Answered by
1
Explanation:
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(a) Squeezing a piece of lemon between the fingers to extract its juice.
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