A resistance r draws power p when connected to an ac source
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Hello Dear.
Here is the answer---
→→→→→→→→→→
Given Conditions---
Resistance = r
Power of the ac source = p
We know, the Relation between the Power and the Resistance---
P = I² × R
Where, I = Current.
Proof---
By the definition of the Potential difference, work done to move a charge Q through a potential Difference V is
W = Q × V
But, Q = I × t
Thus, W = VI × t
Using Ohm's Law, V = I × R
⇒ W = I² × R × t
Using the Formula,
⇒
⇒ P = I² × R
Also, V = I × R
⇒ I = V/R
Thus, P = V² × R
By knowing any of the value as per as the Question, we can easily calculate the Others values by simply using the Proved Formulas.
→→→→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
Here is the answer---
→→→→→→→→→→
Given Conditions---
Resistance = r
Power of the ac source = p
We know, the Relation between the Power and the Resistance---
P = I² × R
Where, I = Current.
Proof---
By the definition of the Potential difference, work done to move a charge Q through a potential Difference V is
W = Q × V
But, Q = I × t
Thus, W = VI × t
Using Ohm's Law, V = I × R
⇒ W = I² × R × t
Using the Formula,
⇒
⇒ P = I² × R
Also, V = I × R
⇒ I = V/R
Thus, P = V² × R
By knowing any of the value as per as the Question, we can easily calculate the Others values by simply using the Proved Formulas.
→→→→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
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