Question

A resistance R ohms is connected in series with parallel circuit comprising two resistance of 8 & 12 ohms respectively. The total power dissipated in the circuit is 70watt when applied voltage is 20v. Calculate the R

Answer 1

Answer:

Explanation:

resistance=8+12=30

V=IR

R= V/I

R=20÷70=3.5 ohm

Answer 2

The required value of R is 3.5 ohms.

GIVEN: A resistance R ohms is connected in series with a parallel circuit comprising two resistance of 8 & 12 ohms respectively. The total power dissipated in the circuit is 70watt when the applied voltage is 20v.
TO FIND: The value of R
SOLUTION:

As we are given in the question,

A resistance R ohm is connected in series with a parallel circuit comprising two resistance of 8 & 12 ohms respectively. The total power dissipated in the circuit is 70watt when the applied voltage is 20v.

Therefore, the following conclusions can be drawn:

Total Resistance=8+12=30

Also, we know,

V=IR

Implying that,

R= V/I

Putting the known values in the formula,

We get,

R =20÷70

R =3.5 ohm

Therefore,

The required value of R = 3.5 ohms.

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