A resistance wire connected in the left gap of a metre bridge balances a 10 Ω resistance in the right gap at a point which divides the bridge wire in the ratio 3 : 2. If the length of the resistance wire is 1.5 m, then the length of 1 Ω of the resistance wire is :
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Answer:
Given,
R:S=3:2
S=10Ω
Ratio,
S
R
=
2
3
R=
2
3
×10=15Ω
The length of 1Ω wire is given by
l=
15
1.5
l=
10
1
⇒0.1 m or 1.0×10
−1
m
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