A resistive potential divider R1R2 with a resistance of 5Kohm and a shaft stroke of 125 mm is used in the arrangement shown in fig (a). Potentiometer R3R4 has a resistance is such that R1= R2 i.e. the wiper is at midstroke. At the start of the test of 5Kohm and e= 5.0 V. The initial position to be used as reference point is such that R1=R2. is adjusted so that the bridge is balanced and e= 0 V Assuming that the displacement is being measured will move a maximum distance of 12.5 mm towards A, calculate the value of e.
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Thus the value of voltage is 0.5 V
Explanation:
We are given that:
- Resistance = 5 K ohm
- Shaft stroke = 125 mm
- Voltage = 5.0 V
- To Find: Value of e = ?
Solution:
We know that 125 mm corresponds to 5000 Ω
Now for 75 mm = 5000 / 125 x 75 = 8000 Ω
Now for Voltage Vo:
Vo = 5 v x (3000 / 5000 - 2500 / 5000 ) = 0.5 V
Thus the value of voltage is 0.5 V
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