a resistor having resistance of 5 ohm is connected accross the cell of 5 V .current passes through resistor is 0.4.the total power produced by battery is
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Answered by
2
Answer:
power = potential difference × current
P = V×I
P = 5 × 0.4
P= 2 watt = 2W
Answered by
1
Answer:
R1 = 5 ohms
R2 = 10 ohms
Voltage, pd. = 5V
Current, I1
I1 = V/R1
I1 = 5/5 A
I1 = 1 A
Now, the second resistor is added
I2 = V/(R1 + R2)
I2 = 5/15
I2 = 0.33 A
So, The value has changed.
The difference is 0.67 A.
You might be confused with the fact that Electric current remains same when resistors are connected in series. But, In this case, Another resistor is added and was not initially present. That's why we got two values.
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