Question

A resistor is marked with the following coloured bands:Red, Red, Red, Gold. The value of the resistor will be:


a)222 Ω 5%
b)2.2 kΩ 5%
c)22.2 kΩ 5%
d)222 kΩ 5%​

Answer 1

Answer:

b) 2.2 kΩ 5%

Explanation:

Resistance colour coding

from left to right,

1st band is for 1st digit,

2nd band is for 2nd digit,

3rd band is for multiplayer

4th band is of tolerance%,

Red is assigned as 2,

and 5% tolerance as gold,

so,

R=22×10^2

R=2200=2.2 kΩ 5%.

Answer 2

Given : The colour markings of the resistor is Red, Red, Red, Gold.

To find : The value of resistor.

Solution :

The value of resistor is, 2.2 kΩ ±5%

We can simply solve this numerical problem by using the following process. (our goal is to calculate the value of the given resistor from its colour marking)

Now,

First and second colour band = Digit (significant figure)

Third colour band = Multiplier

Fourth colour band = Tolerance

Given colours = Red and Gold

According to colour coding chart,

Red = 2 , and , Gold = ± 5% tolerance

So, the values of different colour bands will be :

1. Red = 2 (digit)
2. Red = 2 (digit)
3. Red = ×10² (multiplier)
4. Gold = ± 5% (tolerance)

Value of the resistor = (22 × 10²)Ω ±5% = 2200 Ω ±5% = 2.2 kΩ ±5%

(This will be considered as the final result.)

Hence, the value of resistor is, 2.2 kΩ ±5%