Question

A resistor of 10 ohm is connected across a cell of emf 12v and draws a current of 1.1

a.the internal resistance is

Answer 1

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Answer 2

Ohm’s Law

i = E / (R + r)

Putting the Values,

⇒ 1.1 = 12 / (10 + r)

⇒ 11 + 1.1r = 12

⇒ 1.1r = 1

⇒ r = 1 / 1.1

⇒ r = 10/11 Ω

∴ Internal resistance of battery is 10/11 Ω