Question

a resistor of 5 ohm is connected in series with a parallel combination of a no. of resistor each of 6 ohm If the total resistance of the combination is 7 ohm how much resistor are in parallel

Answer 1

R combined = 7 ohm

R1 = 5 ohm

R2 = 6 ohm

Number of resistances in parallel = n

R combined = R1 + R parallel

7 = 5 + R parallel

R parallel = 2 ohms

1/(R parallel) = 1/R2+1/ R2+...(n times)

1/(R parallel) = n/6

1/2 = n/6

n = 6/2

n = 3

Therefore 3 resistors are there in parallel.

Hope this helps.

Answer 2

Answer:

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