Question

A resistor of 50 ohm, an inductor of (20/pi) H and a capacitor of (5/pi) uF are connected in series to a
voltage source 230 V, 50 Hz. Find the impedance of the
circuit​

Answer 1

Answer:

I = 4.6 A

Step-by-step explanation:

In given LCR circuit -

Xl = 2πfL

Xl = 2π × 50 × 20/π

Xl = 2000 ohm

Also,

Xc = 1/(2πfC)

Xc = 1 / (2π × 50 × 5/π × 10^-6)

Xc = 2000 ohm

Impendence of circuit will be -

Z = √[R^2 + (Xl-Xc)^2]

Z = √[50^2 + (2000-2000)^2]

Z = √(50^2)

Z = 50 ohm

Current in the circuit will be -

I = V / Z

I = 230 / 50

I = 4.6 A

so, current in the circuit is 4.6 A.

HOPE IT HELPS!!