A resistor of 8 ohm is connected in parallel with another resistor x.the resultant resistance of the combination is 4.8.what is the value of resistor x
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For two resistors in parellel
R = R₁R₂/(R₁ + R₂)
4.8 = 8x / (8 + x)
38.4 + 4.8x = 8x
38.4 = 3.2x
x = 38.4/4.2
x = 12
∴ Value of resistor x is 12 Ω
R = R₁R₂/(R₁ + R₂)
4.8 = 8x / (8 + x)
38.4 + 4.8x = 8x
38.4 = 3.2x
x = 38.4/4.2
x = 12
∴ Value of resistor x is 12 Ω
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