Question

A resistor of 8ohm is connected in parallel with another resistor X. The resulant resistance of the combination is 4.8ohm. What is the value of X ?

Answer 1

Given that two resistance R1 and R2 are connected in parallel.

So resultant resistant = 1/ R= 1/R1+1/R2
Here 
R=4.8 ohms
R1= 8ohms
R2= X ohms

1/4.8 =1/8+1/X
10/48 = 8+x/8x
10(8x) =(8+x)48

80x=8x48 +48x

80x-48x=384

32x=384

x=384/32

x=12 ohms

∴ The value of X is 12ohms

Answer 2

Answer:

Here is the solution