Question

A resonant ac circuit contains a capacitor of capacitance 10⁻⁶ F and an inductor of 10⁻⁴ H. The frequency of electrical oscillations will be
(a) 10⁵ Hz
(b) 10 Hz
(c) $\frac{10^5}{2\pi}Hz$
(d) $\frac{10}{2\pi} Hz$

Answer 1

Correct Answer : option C= 10⁵/2π

Explanation :

capacitance =10⁻⁶ F

inductor = 10⁻⁴ H

formula :

ν=1/2π√LC

=1/2π√10⁻⁶10⁻⁴

=10⁵/2π

Answer 2

Option C is correct.

$\frac{10^5}{2\pi}Hz$