Question

A restaurant has two dining rooms. The first room has 16 tables, and the second room has 12 tables.
There are 24 more chairs in the first room than in the second.
If all the tables have the same number of chairs, how many chairs do the two dining rooms have in total?

Answer 1

Given:

• Number of dining rooms = 2
• Tables in the first room = 16
• Tables in the second room = 12
• Chairs in the first room = 24 + the chairs in the second room
• All tables have the same number of chairs

To find:

Number of chairs the two dining rooms have in total

Solution:

Let us denote the number of chairs a table has as x.

So, number of chairs in the first room = 16x (because all the tables have same number of chairs)

Number of chairs in the second room = 12x

Now, chairs in the first room [16x] = 24 + chairs in the second room [12x]

The following equation is formed:

⇒ 16x = 24 + 12x

⇒ 16x - 12x = 24

⇒ (16 - 12)x = 24

⇒ 4x = 24

⇒ x = 24/4

⇒ x = 6

So, the number of chairs a table has is 6.

Number of chairs the two dining rooms have in total = 12x + 16x

= 28x

= 28 × 6

= 168 chairs

Therefore, the two dining rooms have 168 chairs in total.

Answer 2

Given : A restaurant has two dining rooms.

The first room has 16 tables, and the second room has 12 tables.

There are 24 more chairs in the first room than in the second.

 all the tables have the same number of chairs,

To Find :  how many chairs do the two dining rooms have in total

Solution:

Let say each table has  C chairs

Then 16 tables has 16C  chairs

and 12 tables has   12C  chairs

Hence extra chairs in First room = 16C - 12C  = 4C  Chairs

Extra Chairs = 24

Hence 4C  = 24

=> C =  6

Hence 6 chairs for each table

Total Table = 16 + 12 = 28

Hence Total Chairs = 28 * 6  =  168  

the two dining rooms have in total = 168 Chairs

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