Question

A restaurant offers 5 choices of appetizer, 10 choices of main meal, and 4 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming all choices are available, how many different possible meals does the restaurant offer?​

Answer 1

Answer:

there are 3 meals

Step-by-step explanation:

$(x + y + z) = (x + y +z )(x - y - z)$

to find we us

$5 = x \\ y =10 \\ z = 4$

by putting the value in above formula

$(5 + 4 + 10) = (4 + 5 + 10)(4 - 5 -10)\\ \\ (19) = (19)( - 20) = x \\ (19) = (19 \times - 20) = x\\ (19) = (380) = x \\ (19) \div 380 = x \\ 20 = x$

$so \: restunts \: share \: 20 \: deals$