A restaurant sells burgers and fries. If two burgers and one order of fries cost $5.10, and one burger and two orders of fries cost $4.80, how much is one burger and one order of fries?
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Answer: Burger $ 1.80, Fries $ 1.50
Step-by-step explanation:
Application of Simultaneous Equations;
let :Burgers = x
let :Fries = y
Equation 1: 2x + y = 5.10
Equation 2: x + 2y = 4.80
let y be the subject of the formula in Equation 1
Equation 3: y = 5.10 - 2x
Substitute Equation 3 in Equation 2
In the place of y, substitute 5.10 - 2x
x + 2(5.10 - 2x) = 4.80
x + 10.20 - 4x = 4.80
Transpose & Add like terms
-3x = -5.80
Divide by negative 3 both sides
x = 1.80
substitute the value of x in Equation 3
y = 5.10 - 2(1.80)
y = 1.50
Therefore one Burger costs: $ 1.80 and one order of fries : $ 1.50
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