Question

A restaurant serves two special dishes A and B its customers consisting of 60% of men and 40 %

women. 80% of the men order dish A and the rest order dish B. 70% of the women order dish B and

the rest order dish A. In what ratio should the restaurant prepare the two dishes? (Conditional

Probabilty)​

Answer 1

Answer:

3:2

Step-by-step explanation:

Let say total customer = 100C

Men = 60C

Women = 40C

80% of men order dish A = (80/100)60C = 48C

Rest order Dish B = 60C - 48C = 12C

70% of Woman order B = (70/100)40C = 28C

Rest order Dish A = 40C - 28C = 12C

Dish A = 48C + 12C = 60C

DishmB = 12C + 28C = 40C

ratio of dishes A to B restaurant should prepare = 60C : 40C

= 6:4

= 3:2