A retallic disc is being heated. Its area 'A' (in m?) at any time 't' (in second) is
A=5t^2 +4t +8. The rate of increase of area at t = 3s is
1) 34m%s" 2) 26m's-1 3) 14m²s1 4) 42m%s-1
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Answer:
dA/dt = 34 sq units per second
Concept:
If y varies with x, then the rate of change of y with respect to x is \frac{dy}{dx}
Given:
A=5t^2 +4\:t +8
Differentiate with respect to 't'
dA/dt = 5(2t) + 4(1) +0
dA/dt = 10t+4
At t=3 sec,
dA/dt = = 10(3)+4
dA/dt = 30 + 4
dA/dt = 34 sq units per second
Explanation:
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