Physics, asked by kirariyalight7, 1 month ago

a retarding force of 150 n is applied to a body of mass 50 kg which is moving with a speed of 30 metre per second the time taken by the body to come to rest is

please ans fast​

Answers

Answered by Yuseong
7

Answer:

10 s

Explanation:

As per the provided information in the given question, we have :

  • Force applied (F) = –150N (As the force is regarding)
  • Mass (m) = 50 kg
  • Initial velocity (u) = 30 m/s
  • Final velocity (v) = 0 m/s (As it comes to rest)

We are asked to calculate the time taken by the body to come to rest.

In order to calculate the time taken by the body to come to rest, we'll be using the formula of force from the second law of motion. According to the second law of motion,

\longmapsto\bf {F = ma } \\

  • F denotes force
  • m denotes mass
  • a denotes acceleration

Acceleration is the rate of change in velocity, so it can be written as,

\longmapsto\rm {F = m\Bigg ( \dfrac{v-u}{t}\Bigg) } \\

Substitute the values in the above equation.

\longmapsto\rm {-150 = 50 \Bigg ( \dfrac{0-30}{t}\Bigg) } \\

\longmapsto\rm {\dfrac{-150}{50} = \Bigg ( \dfrac{0-30}{t}\Bigg) } \\

\longmapsto\rm {-3=  \dfrac{-30}{t}} \\

\longmapsto\rm {-3t = -30} \\

\longmapsto\rm {t =\cancel{\dfrac{ -30}{3}} } \\

\longmapsto\bf {t = 10 \; s} \\

Therefore, the time taken by the body to come to rest is 10 seconds.

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More Information :

  1. Force is defined as push or pull which tends the position, shape, speed of the object.
  2. SI unit of force is Newton.
  3. Newton is denoted by N.
  4. Force is also the product of mass and acceleration, i.e Force = Mass × Acceleration

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