Physics, asked by sandhyana5, 4 months ago

A reversible heat engine absorbs

4 points

2500kJ/cycle of heat from a

constant temperature heat source at

2000K, and rejects some energy as

waste heat to a reservoir X. The work

output from the engine is used to

drive a reversible refrigerator: its

source temperature being 300K. The

heat outflow from the refrigerator is

also taken to the reservoir X. The

total heat flow in to the reservoir is

3000kJ/cycle. Calculate the work

output from the heat engine and

temperature of reservoir X. Sketch

the system showing the reservoirs

and direction of work and heat flow.

Step marks to be given.

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Answers

Answered by diyakhrz12109

QUESTION : A heat engine is supplied with 250 kJ/s of heat at a constant fixed temperature of 227^0 C; the heat is rejected at 27 ^0 C, the cycle is reversible, then what amount of heat is rejected?

ANSWER : The temperature in kelvin scales are T 1

=273+27=300K,T 2 =273+237=500K

T1 is temperature of sink And T 2 is temperature of source hence by efficiency we get

η= 1− T1/ T2 =1− Q1 / Q2

Q1= T1 / T2 ∗Q2 = 300 / 500 ∗250 = 150kW

Answered by shubhamchan2000

Answer:answer is in the pdf for your help answer is in 1028 K

Explanation:

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