A reversible heat engine operates with an efficiency of 50%. If during each cycle it rejects 150 cal to a reservoir of heat at 30 °C then what is the temp of the other reservoir?
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The temperature of the other reservoir is 60 degree Celsius.
Explanation:
Efficiency "η" = 50 % = 0.5
η = 1 - T (sink) / T(source)
0.5 = 1 - 30 / T(source)
0.5 = 30 / T(source)
T (source ) = 30 / 0.5 = 60 degree Celsius
Thus the temperature of the other reservoir is 60 degree Celsius.
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