A reversible heat engine receives 50% of its intake heat from a thermal reservoir at 1000 K and the
balance amount from another reservoir at 500 K. However, it rejects heat to a single sink at 275 K.
Determine the maximum possible efficiency this heat engine may register.
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Efficiency = ( work out put / work in put) × 100%
Work input :
1000 + 500 = 1500 K
Work out put :
275 K
Efficiency :
(275 / 1500) × 100%
275/1500 = 0.1833
0.1833 × 100% = 18.33%
Efficiency = 18.33%
Work input :
1000 + 500 = 1500 K
Work out put :
275 K
Efficiency :
(275 / 1500) × 100%
275/1500 = 0.1833
0.1833 × 100% = 18.33%
Efficiency = 18.33%
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