A revolver of mass 500 g fires a bullet of mass l0g with a speed of 100 m/s. Find the :
(a) Momentum of the bullet.
(b) Initial momentum of ‘revolver & bullet’ as a system.
(c) Recoil velocity of the revolver.
Answers
Solution :
As per the given data ,
- Mass of the revolver = 500 g
- Mass of the bullet = 10g
- Speed of the bullet = 100 m /s
Let's convert g into kg
In order to do that simply divide by 1000
- Mass of revolver = 0.5 kg
- Mass of bullet = 0.01 kg
_______________________
(a) Momentum of bullet
Momentum of bullet
= mass of bullet × speed of bullet
= 0.01 kg × 100
= 1 kg m/s
Momentum of bullet = 1 kg m/ s
___________________________
(b) Initial momentum of the system
Initial momentum of the system
= momentum of bullet + momentum of revolver
= mass of bullet × velocity of bullet + mass of revolver × velocity of revolver
= 0.01 × 0 + 0.5 × 0
Initially the entire system is at rest
= 0
The initial momentum of the entire system is zero
________________________
( c) Recoil velocity of the revolver
In order to solve this let us use the concept of law of conservation of momentum
Initial momentum of the system will be equal to the final momentum
P initial = P final
0 = mass of bullet × velocity of bullet + mass of revolver × velocity of revolver
mass of bullet × velocity of bullet =
mass of revolver × velocity of revolver
0.01 × 100 = - 0.5 × V recoil
V recoil = - 1 / 0.5
V recoil = - 2 m / s
The recoil velocity of the revolver is - 2 m/s
Explanation:
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