Question

A revolver of mass 500g fires a bullet of mass 10g with a speed of 100m/s find momentum of bullet . initial momentum of revolver and bullet system. recoil velocity of the revolver

Answer 1

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Answer 2

Hey dear,

◆ Answer-
a) Initial momentum of system = 0
b) Final momentum of bullet = 1 kgm/s
c) Recoil velocity of revolver = 2 m/s

◆ Explanation-
# Given-
m1 = 10 g = 0.01 kg
m2 = 500 g = 0.5
v1 = 100 m/s
v2 = ?

# Solution-
Initially both revolver and bullet are at rest.
Initial momentum of system is-
p1 = m1u1 + m2u2
p1 = 0.01×0 + 0.5×0
p1 = 0

Final momentum of system is-
p2 = m1v1 + m2v2
p2 = 0.01×100 + 0.5×v2
p2 = 1 + 0.5v2

By law of conservation of momentum-
p1 = p2
0 = 1 + 0.5v2
v2 = -1/0.5
v2 = -2 m/s

Therefore,
a) Initial momentum of system = 0
b) Final momentum of bullet = 1 kgm/s
c) Recoil velocity of revolver = 2 m/s

Hope this helps...