A rheostat has 100 turns of wire of radius 0.4 radius
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◆ Complete question -
Q. A rheostat has 100 turns of a wire of radius 0.4 mm having resistivity 4.2×10^-7ohm metre. The diameter of each turn is 3 cm. What is the maximum value of resistance that it can introduce?
● Answer -
R = 7.876 ohm
● Explanation -
Total length of wire is calculated by -
l = n × 2πR
l = 100 × 2 × 3.142 × 1.5×10^-2
l = 9.426 m
Cross sectional area of wire is -
A = πr^2
A = 3.142 × (0.4×10^-3)^2
A = 5.026×10^-7 m^2
Maximum value of resistance is given by -
R = ρl/A
R = 4.2×10^-7 × 9.426 / 5.026×10^-7
R = 7.876 ohm
Hence, the maximum value of resistance that the wire can introduce is 7.876 ohm.
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