Question

A rhombus has diagonals that measure 6 and 8 cm what is its area how much does each side measure

Answer 1

area of rhombus =
$\frac{1}{2} \times product \: of \: diagonals$
=
$\frac{1}{2} \times 8 \times 6 \\ = 24$
now length of each side square
=sum half of length of diagonals square

$= \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{25} \\ = 5$