Question

A rhombus has diagonals that measure 6 cm and 8 cm. What is its area? How much does each side measure?​

Answer 1

Answer:

Here's the answer below!!!✌️

Step-by-step explanation:

The Diagonals of rhombus is 6,8cm

The area of rhombus is given as

1/2×6×8

Thus required area of rhombus is 24 cm²

The diagonals of the rhombus bisect each other at right angles

So the sides of right triangle formed by diagonals and sides are 3,4

So by pythagoras theorem

side² = 3² + 4²

side² = 16 + 9

side² = 25

side = √25

side = 5

Hence, length of side is 5 cm.

Hope so ,this answer will be helpful for uhh!!✨✌️

Answer 2

Answer:

Step by Step explanation:

The Diagonals of rhombus is 6,8cm

The area of rhombus is given as 21×6×8

Thus required area of rhombus is 24 cm2

The diagonals of the rhombus bisect each other at right angles

So the sides of right triangle formed by diagonals and sides are 3,4

So by pythagoras theorem 

Side2=32+42side2=16+9side2=25side=25Side=5

Hence length of side is 5 cm