a rhombus has perimeter 100m and one of iths diagonal is 40 m area of the rhombus is
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Answer:
600m
2
Perimeter of rhombus =4×side
⇒ 100=4×side
⇒ side=
4
100
⇒ side=25
We know diagonals of a rhombus divides the rhombus in two equilateral triangle.
Now, we are going to find area of 1 equilateral triangle.
Semi perimeter =
2
25+25+40
=45
We will use Heron's formula to find are of equilateral triangle.
⇒ Area of triangle =
s(s−a)(s−b)(s−c)
=
45(45−40)(45−25)(45−25)
=
45×5×20×20
=
90000
=300m
2
⇒ Area of rhombus =2×300m
2
=600m
2
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