Question

a rhombus has perimeter 100m and one of iths diagonal is 40 m area of the rhombus is
pls thank my answers pls ​

Answer 1

Answer:

Perimeter of rhombus = 4 x side

⇒ 100 = 4 x side

⇒ side = 100 4

⇒ side = 25

We know diagonals of a rhombus divides the rhombus in two equilateral triangle. Now, we are going to find area of 1 equilateral triangle.

Semi perimeter

25 + 25 + 40

= 45

2 We will use Heron's formula to find are of equilateral triangle.

Feedback

→ Area of triangle = √s(s – a) (s – b)(s – ‹

=

/45(45 – 40) (45 – 25) (45 – 25)

= √45 x 5 x 20 × 20 = √90000 =

300 m²

→ Area of rhombus = 2 × 300 m² = 600 m²